Bainternet的答案为您提供了一个查询的用户数，如果您需要多个页面的用户，它也没有帮助。

如果你有成千上万的用户，那不是你想要的。您可以使用WP\\u User\\u Query，就像您对帖子使用WP\\u Query一样。这与get\\u用户非常相似——参数相同，但特性和用法不同。

最重要的是你可以the total number of users who match your criteria 没有实际返回所有结果（并且可能达到内存限制）。

Usage

$user_query = new WP_User_Query(array(
    \'number\' => 15,
    \'paged\' => 1
));

$users = $user_query->get_results(); // array of WP_User objects, like get_users

$total = $user_query->get_total(); // int, total number of users (not just the first page)

Examples:

echo $users[0]->get(\'display_name\');
// "Radley Sustaire"

echo count($users);
// "15" (count from the first page of users)

echo $user_query->get_total();
// "86" (count from all pages of users)

$num_pages = ceil( $user_query->get_total() / 15 );
// "6" (number of pages of users. 15 is the "users per page" from the first example)
//     (* do NOT use count($users) in place of 15. try a separate $per_page variable)

我是如何实现这一点的：

function getUsers($args = array(), $count = false)
{
    // Default behaviour is to return full user information
    $method = \'get_results\';

    // If count is true then change the WP_User_Query method
    // and limit the fields SELECT\'d to \'ID\' to speed up the query
    if($count === true) {
        $method = \'get_total\';
        $args[\'fields\'] = \'ID\';
    }

    $userQuery = new WP_User_Query($userArgs);

    return call_user_func(array($userQuery, $method));
}

$args = array(\'role\' => author,
              \'meta_key\' => \'foo\',
              \'meta_value\' => \'bar\'
        );

// Returns (array) WP_User objects (a la get_users())
$users = getUsers($args);

// Returns (int) number of of users matched by $args
$count = getUsers($args, true);

尝试以下函数以获取数组中所有用户的计数，以及基于用户角色的用户计数：

count_users();

Array (
    [total_users] => 32
    [avail_roles] => Array (
        [administrator] => 1
        [subscriber] => 28
        [sub_administrator] => 1
        [editor] => 2
    )
)