从分类对象获取ID和slug

我有一个自定义字段来选择一个类别（自定义分类法），然后我将显示其所有子类别的列表。当我将自定义字段作为“term\\u id”返回时，这可以正常工作

然而我还想从这个选定的类别（父类别）中获取slug，这样我就可以链接到它的类别页面（我想我不能用ID链接到它）。所以我想也许我应该将自定义字段作为对象返回。这是它转储的内容：

 stdClass Object ( [term_id] => 122 [name] => Quick Release Watch Bands [slug] => fits-all [term_group] => 0 [avhec_term_order] => 0 [term_taxonomy_id] => 122 [taxonomy] => product_cat [description] => Watch bands in many colors [parent] => 0 [count] => 293 [meta_id] => 1 [woocommerce_term_id] => 122 [meta_key] => order [meta_value] => 22 )

你知道我怎样才能从中取出ID（122）和slug（适合所有人）吗？这是到目前为止我的代码。自定义字段称为“selected\\u category”。

<?php $catid = get_sub_field(\'selected_category\');  

            $args = array(
              \'taxonomy\'     => \'product_cat\',
              \'orderby\'      => \'name\',
              \'show_count\'   => 0,
              \'pad_counts\'   => 0,
              \'hierarchical\' => 1,
              \'title_li\'     => \'\',
              \'depth\'        => 1,
              \'child_of\'     => $catid
            );

            ?> 

<h4><a href="URL.COM/NEED-CATEGORY SLUG"><?php the_sub_field(\'title\'); ?></a></h4>

<ul class="subcats">
<?php wp_list_categories( $args ); ?>
</ul>

谁能帮帮我吗？非常感谢你！

<?php $catid = get_sub_field(\'selected_category\'); $term_link = get_term_link( intval( $catid ), \'product_cat\' ); ?> <h4><a href="<?php echo esc_url( $term_link ); ?>"><?php the_sub_field(\'title\'); ?></a></h4>

stdClass Object ( [term_id] => 122 [name] => Quick Release Watch Bands [slug] => fits-all [term_group] => 0 [avhec_term_order] => 0 [term_taxonomy_id] => 122 [taxonomy] => product_cat [description] => Watch bands in many colors [parent] => 0 [count] => 293 [meta_id] => 1 [woocommerce_term_id] => 122 [meta_key] => order [meta_value] => 22 )

<?php $catid = get_sub_field(\'selected_category\'); $args = array( \'taxonomy\' => \'product_cat\', \'orderby\' => \'name\', \'show_count\' => 0, \'pad_counts\' => 0, \'hierarchical\' => 1, \'title_li\' => \'\', \'depth\' => 1, \'child_of\' => $catid ); ?> <h4><a href="URL.COM/NEED-CATEGORY SLUG"><?php the_sub_field(\'title\'); ?></a></h4> <ul class="subcats"> <?php wp_list_categories( $args ); ?> </ul>

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从分类对象获取ID和slug

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