我正在使用WP作为我的站点的框架，我有一堆自定义表
现在我需要允许用户向各种实体写评论。假设一个实体是图像，我希望用户对我的图像进行评论。

我该如何使用wp_insert_comment() 当我只有图像ID而没有帖子ID时？（图像与帖子无关）。

示例：

使用jQuery，我执行以下函数：

public function addComment(){
    $data = array(
        \'comment_post_ID\' => 123,
        \'comment_author\' => \'Steven\',
        \'comment_author_email\' => \'[email protected]\',
        \'comment_author_url\' => \'http://www.storelocator.com\',
        \'comment_content\' => \'Lorem ipsum dolor sit amet...\',
        \'comment_author_IP\' => \'127.0.0.1\',
        \'comment_agent\' => \'Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.6; fr; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3\',
        \'comment_date\' => date(\'d-m-Y H:i:s\'),
        \'comment_date_gmt\' => date(\'d-m-Y H:i:s\'),
        \'comment_approved\' => 0,
    );

    $comment_id = wp_insert_comment($data);
    echo \'Comment ID: \'.$comment_id;
}

这是可行的。问题是没有ID为123的帖子。因此，当我转到我的管理界面时，会收到如下错误消息：

注意：尝试在/var/www/storelocator/wp-includes/capabilities中获取非对象的属性。php在线1178

注意：正在尝试获取/var/www/storelocator/wp admin/includes/class wp comments列表中非对象的属性。php在线488

我有没有办法解决这个问题？

Update
我正在尝试添加一些元数据，但中未触发该函数functions.php.

这是我目前使用的代码：

// Comment submit on a car
http://mysite.com/wp-content/themes/mytheme/include/jquery.php?action=addComment&entity=car&entity_id=247

// My web service
 - More or less as above. I\'ve added two fields:

  \'entity\' => $_REQUEST[\'entity_id\'],
  \'entity_id\' => $_REQUEST[\'entity\']

I\'ve also created a post, and using this post ID for comment_post_ID.


// functions.php - This is not triggered
add_action(\'comment_post\', \'pre_handle_comment\');

function pre_handle_comment($comment_id){
  add_comment_meta($comment_id, \'entity\', $_POST[\'comment_type\']);
  // Also tried
  add_comment_meta($comment_id, \'entity\', \'car\');
}

\'supports\' => array(
    \'comments\',
),

add_action( \'wp_insert_comment\', \'prefix_comment_meta\', 10, 2 );

function prefix_comment_meta( $id, $comment )
{
    // evaluate POST request and create comment meta
}