如何使用一个AJAX调用和PHP函数返回两个JSON对象？非常感谢您的帮助！
下面是PHP函数：
function get_ldap_attr() {
header("Content-type: application/json");
$lan = $_POST[\'lan\'];
$dn = get_site_option ( "ldapServerOU" );
$usr = get_site_option ( "ldapServerCN" );
$pw = get_site_option ( "ldapServerPass" );
$addr = get_site_option ( "ldapServerAddr" );
$ad = ldap_connect ( $addr )
or die ( "Connection error." );
ldap_set_option ( $ad, LDAP_OPT_PROTOCOL_VERSION, 3 );
ldap_set_option ( $ad, LDAP_OPT_REFERRALS, 0 );
$bind = ldap_bind ( $ad, $usr, $pw );
if ( $bind ) {
$SearchFor ="cn=".$lan;
$result = ldap_search ( $ad,$dn,$SearchFor );
$entry = ldap_first_entry ( $ad, $result );
if ( $entry != false ) {
$info = ldap_get_attributes ( $ad, $entry );
}
$comm = stripos ( $info[\'manager\'][0], \',\' );
// find position of first comma in CN=Mxxxxxx,OU=Users,OU=MCR,DC=mfad,DC=mfroot,DC=org (directReports field)
$eq = stripos ( $info[\'manager\'][0], \'=\' );
// find position of first =
$s_lanid = substr ( $info[\'manager\'][0], $eq+1, ( ( $comm-1 ) - ( $eq ) ) );
//get substring between = and comma... for lanid happiness..
$sup = getLDAPInfo ( $s_lanid, $bind, $ad, $dn );
// get supervisor\'s info...
}
echo json_encode($sup);
die();
}
以及jQuery：
jQuery(function() {
jQuery(\'#empLanId\').on(\'blur\', function() {
var lan = jQuery(\'#empLanId\').val();
var ajaxurl = \'<?php echo admin_url("admin-ajax.php", null); ?>\';
var data = { action: "get_ldap", lan: lan};
jQuery.ajax({
type: \'POST\',
url: ajaxurl,
data: data,
dataType: \'json\',
success: function(response) {
jQuery(\'#empSupLanId\').val(response.lanid);
jQuery(\'#empSupName\').val(response.fullname);
jQuery(\'#empSupNumber\').val(response.phone);
}
});
});
});
最合适的回答,由SO网友:M-R 整理而成
如果我理解正确，您需要将它们包装在一个数组中并传递给Javascript。
function get_ldap_attr() {
header("Content-type: application/json");
...
// suppose you want to return $second_var
echo json_encode(array($sup,$second_var));
die();
}
JSON请求的成功函数将以数组的形式接收它们。您可以使用整数索引访问它们。
jQuery(function() {
jQuery(\'#empLanId\').on(\'blur\', function() {
var lan = jQuery(\'#empLanId\').val();
var ajaxurl = \'<?php echo admin_url("admin-ajax.php", null); ?>\';
var data = { action: "get_ldap", lan: lan};
jQuery.ajax({
type: \'POST\',
url: ajaxurl,
data: data,
dataType: \'json\',
success: function(response) {
response[0] // first $sup variable
response[1] // second $second_var variable
//jQuery(\'#empSupLanId\').val(response.lanid);
//jQuery(\'#empSupName\').val(response.fullname);
//jQuery(\'#empSupNumber\').val(response.phone);
}
});
});
});
SO网友:Razon Komar Pal
jQuery Code:
(function ($) {
\'use strict\';
$(function () {
var value_1 = 10;
var value_2 = 20;
$(\'.btn\').on(\'click\', function(){
$.ajax({
url: \'your_ajax_url_here\',
type: \'POST\',
data: {
action : \'action_name\',
val_1 : value_1,
val_2 : value_2,
},
beforeSend: function () {
console.log(\'Sending....\');
},
success: function (response) {
var obj = JSON.parse(response);
console.log(obj);
},
error: function (errorThrown, status, error) {
console.log( status );
}
});
})
});
})(jQuery);
PHP Code:
function get_ldap_attr() {
$obj_val_1 = $_POST[\'val_1\'];
$obj_val_2 = $_POST[\'val_2\'];
echo json_encode(array(
\'obj_1\' => $obj_val_1,
\'obj_2\' => $obj_val_2,
));
}
仅此而已。
