我试图显示事件生产者的列表，这些生产者存储为分类法。对于每个事件（自定义帖子类型），可以有1到多个生产者，所以我想列出它们，用逗号分隔，并带有“&；”在倒数第二个和最后一个之间。除了只有一个制作人的情况外，以下函数完成此工作。我该如何让这一点同时适用于一个制片人或多个制片人？

function the_producers($post_id = false) {
    if ($post_id == false) {
        $post_id = get_the_ID();
    }
    $producers = get_the_terms($post_id, \'producers\');
            $prods = array();
    foreach ($producers as $producer) {
            $prods[] = $producer->name;
    }
    $str = array_pop($prods);
    if ($prods) {
        $str = implode(\', \', $prods).\' & \'.$str;
        return $str;
    } else {
        return false;
    }   
}

我尝试计算迭代次数，如果只有1次，只返回单个生产者，但由于某种原因，这似乎没有显示任何内容：

function the_producers($post_id = false) {
    if ($post_id == false) {
        $post_id = get_the_ID();
    }
    $producers = get_the_terms($post_id, \'producers\');
            $prods = array();
            $cnt = 0;
    foreach ($producers as $producer) {
            $cnt++;
            $prods[] = $producer->name;
    }
    if ($cnt == 1) {
        $str = $producer->name;
    } else {
        $str = array_pop($prods);
        if ($prods) {
            $str = implode(\', \', $prods).\' & \'.$str;
            return $str;
        } else {
            return false;
        }
    }
}

function the_producers($post_id = false) {
    if ($post_id == false) {
        $post_id = get_the_ID();
    }
    $producers = get_the_terms($post_id, \'producers\');
    $q = count($producers);
    if( 1 == $q ) {
        $str = reset($producers)->name;
        return $str;
    } elseif ($q > 1) {
        $prods = array();
        foreach ($producers as $producer) {
        $prods[] = $producer->name;
        }
        $str = array_pop($prods);
        if ($prods) {
            $str = implode(\', \', $prods).\' & \'.$str;
            return $str;
        } else {
            return false;
        }
    } else {
        return false;
    }
}

$q = count($producers);

if( 1 == $q ) {
  // do something when only one term exists
}else{
  // do something for mutliple terms
}