在一个列表中显示来自两个角色的用户

几天前我问了一个问题(link) 关于我在WP 4.1和a中遇到的问题WP_User_Query 我使用自定义元数组运行。我当前的代码在升级到4.1之前一直有效：

    if( is_array($user->role) == true){ 
    $staff_role=esc_attr(implode(", ",$user->role));
    } else {$staff_role=$user->role;};

    $pm = array(
    \'orderby\' => \'display_name\',
    \'meta_query\' => array(
                    \'relation\' => \'OR\',
                        array(
                            \'key\' => $staff_role,
                            \'value\' => \'program_manager\',
                            \'compare\' => \'LIKE\'
                            ),
                        array(
                            \'key\' => $staff_role,
                            \'value\' => \'administrator\',
                            \'compare\' => \'LIKE\'
                            )
                    )
    );
// User Queries
    $program_manager = new WP_User_Query( $pm );
// User Counts
    $pm_count = count($program_manager->results);
// User Loop
    if ( ! empty( $program_manager->results ) ) {
        echo \'<h2>Program Managers (\' . $pm_count . \')</h2>\';
        foreach ( $program_manager->results as $user ) {
            echo \'<li>\',
            pods_user_profile_display($user);
            echo \'</li><div class="clearboth"></div><br />\';
    }
    echo \'<hr />\';
    } else {
    echo \'<h2>Program Managers</h2>No managers found.\';
    }

然而，我没有得到答案。

希望这个新问题能得到答案：

我想在我的网站上的目录中显示一个角色为“管理员”或“程序管理员”的WP用户列表。例如，我有1个administrator 和12program_managers、我希望列表显示所有13个按排序的用户display_name

global $wpdb; $prefix = $wpdb->prefix; $meta_name = "{$prefix}capabilities"; \'meta_query\' => array( \'relation\' => \'OR\', array( \'key\' => "{$meta_name}" \'value\' => \'program_manager\', \'compare\' => \'LIKE\' ), array( \'key\' => "{$meta_name}", \'value\' => \'administrator\', \'compare\' => \'LIKE\' ) ) );

if( is_array($user->role) == true){ # This will break your meta query as it could create "subscriber, administrator" as a key # and your meta query does \'key\' => $staff_role $staff_role=esc_attr(implode(", ",$user->role)); } else { $staff_role=$user->role; }

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