最好的方法是设置一个自定义表。对于每个视图，您将添加一个新行，其中至少包含uid、帖子id和日期/时间。这种方法的美妙之处在于，您可以在每个视图中存储任意多的数据，例如IP或当前用户（如果他们已登录）。我真的不能给出比这更多的建议，因为我从未尝试使用自定义表，但是有很多插件可以做到这一点。The codex article can be found here.

另一种方法是使用post-meta，类似于您的操作方式。您要做的是存储一个查看时间数组。这样，您就不必存储视图计数，尽管我确信您希望保留旧数据以用于记录。然而，这最终会导致一个非常臃肿的函数试图对您的帖子进行排序。

我已经完成了下面的一些代码，理论上应该可以工作，但我还没有机会测试它。

//Track page view
function track_post_view( $post_id ) {
    $views_key  = \'post_views_times\';
    $views = get_post_meta( $post_id, $views_key, true );
    $count = count( $views );

    if( $count === 0 ) {
        $views = array();
    }

    //Adds another entry to the views with the current UNIX timestamp
    $views[] = time();

    return update_post_meta( $post_id, $views_key, $views );
}

//Get all posts

function get_popular_posts( $limit = 3 ) {

    $all_posts = new WP_Query( \'post_type\' => \'post\', \'post_status\' => \'publish\' );

    //Store these posts
    while($all_posts->get_posts()){
        $all_posts->the_post();
        $post_views = get_post_meta( get_the_ID(), \'post_views_times\' );
        $week_ago_time = time() - 7 * 24 * 60 * 60; //This is the timestamp of 1 week ago
        for( $i = 0; $i < count( $post_views ); $i++ ){
            if( $post_views[$i] < $week_ago_time ){ 
                unset($post_views[$i]); //If the timestamp is less than 1 week ago get remove it from the variable
            }
        }
        $posts_list[] = array( \'views\' => count( $post_views ), \'post_id\' => get_the_ID() );
    }

    //Get the column to sort the $posts_list by
    foreach ($posts_list as $key => $row) {
        $views[$key]  = $row[\'volume\'];
    }

    array_multisort( $views, SORT_DESC, $posts_list ); //This sorts descending by views.

    //Get the top 3 viewed posts and store that it yet another array
    for( $i = 0; $i < $limit; $i++ ){
        $most_viewed_ids[] = $posts_list[$i][\'post_id\'];
    }

    $popular = new WP_Query( \'p\' => $most_viewed_ids ); //Run a query getting our 3 top posts

    wp_reset_postdata();

    return $popular;

}