我创建了一个自定义插件和一个小部件。目前,该代码包含在插件的基本php文件中,并且工作正常。我想将小部件和所有未来的小部件移动到一个小部件中。php文件,并将其包含到主插件文件中。当我这样做时,我得到以下php错误。
PHP致命错误:调用/var/www/wordpresstest/wp includes/capabilities中未定义的函数wp\\u get\\u current\\u user()。php在线1387
这是小部件的代码。当我将此代码放在主插件php文件中时,它可以完美地工作,但当我使用require“widgets.php”时,我会出现错误。
<?php
class nb_game_info_widget extends WP_Widget
{
function __construct()
{
parent::__construct(\'nb_game_info_widget\', __(\'Test Widget\', \'nb_game_info_widget_domain\'), array( \'description\' => __( \'Game IDS Widget\', \'nb_game_info_widget_domain\' )));
}
public function widget( $args, $instance )
{
if(is_single())
{
$title = apply_filters( \'widget_title\', $instance[\'title\'] );
echo $args[\'before_widget\'];
if ( ! empty( $title ) )
echo $args[\'before_title\'] . $title . $args[\'after_title\'];
global $post;
$postid = $post->ID;
$gameids = get_post_meta( $postid, \'nb_gameids_key\', true );
$platformids = get_post_meta( $postid, \'nb_platformids_key\', true );
echo "GAME IDS ! = ". $gameids;
//required for the theme to do whatever it does
echo $args[\'after_widget\'];
}
}
// Widget Backend
public function form( $instance ) {
if ( isset( $instance[ \'title\' ] ) )
{
$title = $instance[ \'title\' ];
}
else {
$title = __( \'New title\', \'nb_game_info_widget_domain\' );
}
// Widget admin form
?>
<p>
<label for="<?php echo $this->get_field_id( \'title\' ); ?>"><?php _e( \'Title:\' ); ?></label>
<input class="widefat" id="<?php echo $this->get_field_id( \'title\' ); ?>" name="<?php echo $this->get_field_name( \'title\' ); ?>" type="text" value="<?php echo esc_attr( $title ); ?>" />
</p>
<?php
}
// Updating widget replacing old instances with new
public function update( $new_instance, $old_instance )
{
$instance = array();
$instance[\'title\'] = ( ! empty( $new_instance[\'title\'] ) ) ? strip_tags( $new_instance[\'title\'] ) : \'\';
return $instance;
}
} // Class nb_game_info_widget ends here
// Register and load the widget
function nb_loag_gameinfo_widget() {
register_widget( \'nb_game_info_widget\' );
}
add_action( \'widgets_init\', \'nb_loag_gameinfo_widget\' );
最合适的回答,由SO网友:s_ha_dum 整理而成
I have no idea why this should solve the issue but I can solve it. Use a different file name. For example: include(\'my_widgets.php\');
I get the error you describe with include(\'widgets.php\');
but not with a different file name. I don\'t know why. I do know that WordPress has a Core file named widgets.php
but I can\'t work out why there should be a conflict. It must have to do with the way that include
crawls for files but I\'d have to do some research-- get under the hood, so to speak. Moral of the story: Don\'t use generic file names :)