我正在制作一个包含多个文件的插件，它与wpdb有一些交互，所以我将所有内容都放在一个名为FA db的文件中。php
<?php
global $wpdb;
function FAvideoid()
{
return $wpdb->get_var( "SELECT \'video_id\' FROM $wpdb->ytvideos ORDER BY RAND() LIMIT 1;");
}
function FAregister($id)
{
$wpdb->insert( \'ytvideos\', $id, \'%s\' );
}
function FAsetup()
{
$table_name = $wpdb->prefix . "ytvideos";
$charset_collate = $wpdb->get_charset_collate();
$sql = "CREATE TABLE $table_name ( id mediumint(9) NOT NULL AUTO_INCREMENT, video_id varchar(55) DEFAULT \'\' NOT NULL, UNIQUE KEY id (id)) $charset_collate;";
dbDelta( $sql );
}
?>
并将其包含在我的主文件中
<?php
/*
Plugin Name: Floating Ads
Description: A floating ad that have youtube ads built in
Version: 0.5.0
Author: Henrique Almeida Marcomini
*/
include "FA-db.php";
include "FA-admin.php";
include "FA-ad.php";
add_action( \'admin_menu\', \'FAmenu\' );
add_action( \'wp\', \'FAad\' );
add_action( \'activated_plugin\', \'FAsetup\' );
?>
我不把它包括在其他地方。
但是当我尝试激活插件时，我得到了以下错误
Fatal error: Cannot redeclare FAvideoid() (previously declared in /home/u696621553/public_html/wp-content/plugins/FloatingAds/FA-db.php:7) in /home/u696621553/public_html/wp-content/plugins/FloatingAds/FA-db.php on line 8
最合适的回答,由SO网友:jgraup 整理而成
将函数包装为!function_exists() 以避免重新声明错误。
if( ! function_exists(\'FAvideoid\') ) :
function FAvideoid()
{
return $wpdb->get_var( "SELECT \'video_id\' FROM $wpdb->ytvideos ORDER BY RAND() LIMIT 1;");
}
endif;
或者为了减少代码被多次导入：
include_once "FA-db.php";
include_once "FA-admin.php";
include_once "FA-ad.php";
但最好的方法可能是将两者结合起来：
// Only load files and hook events if your functions haven\'t been defined
if( ! function_exists(\'FAvideoid\') ) :
include_once "FA-db.php";
include_once "FA-admin.php";
include_once "FA-ad.php";
add_action( \'admin_menu\', \'FAmenu\' );
add_action( \'wp\', \'FAad\' );
add_action( \'activated_plugin\', \'FAsetup\' );
endif;
