我是wordpress开发的新手，我有一个包含zipcode值和学校名称的表（表中可能有数千个结果）。我要做的是从用户检索zipcode，并根据zipcode值在表中搜索它，然后根据搜索结果显示与zipcode用户输入的zipcode相关的学校名称。到目前为止，我能够获得zipcode并通过以下方式进行搜索：（这是我现在拥有的经过编辑的部分和最新的代码）

<div class="col-xs-4">
   <div class="zipcode">Zip Codes
      <input type="text" class="form-control postcode" name="postalCode" />
      <input type="button" id="findschoolname">
    </div>
    <div id="replacedropwdown">
    <div class="dropdown">
    <button class="btn btn-primary dropdown-toggle" type="button" data-toggle="dropdown">Institutions
       <span class="caret"></span></button>
          <ul class="dropdown-menu">
             <li><a href="#"</a></li>
           </ul>
     </div>
     </div>
     </div>
<script type="text/javascript">
 jQuery(document).ready(function(){
 jQuery("#findschoolname").click(function(){
 var postcode = jQuery(\'.postcode\').val();
     var postData = {
         action: \'finescroolname\',
         postcode: postcode,
     }
     var adminurl = admin_url( \'admin-ajax.php\' );
 jQuery.post(ajaxurl, postData, function(response) {
 jQuery(\'#replacedropwdown\').html(response);
 });
});
});

以及我的职能。php是：

  add_action( \'wp_ajax_finescroolname\', \'finescroolname\' );
  function finescroolname(){
    global $wpdb;
    $postcode = $_POST[\'postcode\'];
    $school_query = "SELECT DISTINCT schoolname from wp_db where zipcode=\'.$postcode.\'";
    $results = $wpdb->get_results($school_query);
    $html = \'drop down html\';
    echo $html;
    wp_die();
  }

所以我的问题是关于这一部分，我如何才能将这些结果传递到wordpress的下拉列表中？它将与ajax合作吗？有人能帮我写一小段代码，让我得出结果吗？感谢您的时间和关注。因此，通过@user3888958帮助，我可以在ajax帖子中看到结果：

<script type="text/javascript">
jQuery(document).ready(function(){
jQuery("#findschoolname").click(function(){
    var postcode = jQuery(\'.postcode\').val();
    var postData = {
        action: \'finescroolname\',
        postcode: postcode,
    }
    var adminurl = admin_url( \'admin-ajax.php\' );
    jQuery.post(ajaxurl, postData, function(response) {
        jQuery(\'#replacedropwdown\').html(response);
    });
}); 
});
</script>

但当我尝试在函数中调试finesColName（）函数时，它仍然没有将postcode的值传递到下拉列表中。php我在那里看不到任何邮政编码。

<div class="col-xs-4">
      <div class="zipcode">Zip Codes
         <input type="text" class="form-control postcode" name="postalCode" />
         <input type="button" id="findschoolname">
       </div>
       <div id="replacedropwdown"> 

       </div>
</div>
<script type="text/javascript">
jQuery(document).ready(function(){
    jQuery("#findschoolname").click(function(){
        var postcode = jQuery(\'.postcode\').val();
        var postData = {
            action: \'finescroolname\',
            postcode: postcode,
        }
        var adminurl = admin_url( \'admin-ajax.php\' );
        jQuery.post(ajaxurl, postData, function(response) {
            jQuery(\'#replacedropwdown\').html(response);
        });
    }); 
});
</script>

add_action( \'wp_ajax_finescroolname\', \'finescroolname\' );
function finescroolname(){    
    global $wpdb; 
    $postcode = intval( $_POST[\'postcode\'] );

    $school_query = "SELECT DISTINCT schoolname from wp_db where zipcode=\'.$postcode.\'";
    $results = $wpdb->get_results($school_query);
    // Create html here and echo it;
    $html = \'drop down html\';
    echo $html;
    wp_die(); 
}