我正在创建一个插件，当管理员登录时single-{post-type-slug}.php 不存在，该页https://my-site/post-type-slug/my-admin-page.php 无需加载主题css即可显示。
我试过：
wp_dequeue_style(\'screen\');
wp_deregister_style(\'screen\');
wp_dequeue_style(\'style\');
wp_deregister_style(\'style\');
wp_dequeue_style(\'style.css\');
wp_deregister_style(\'style.css\');
wp_dequeue_style( \'wpsl-styles\' );
像这样在我的物体里面。。。
add_action( \'wp_print_scripts\', array( $this , "remove_style" ), 100000 );
or
add_action( \'wp_enqueue_scripts\', array( $this , "remove_style" ), 100000 );
and
public function remove_style(){
wp_dequeue_style( \'wpsl-styles\' );
//wp_dequeue_style("style");
//wp_deregister_style("style");
global $wp_styles;
foreach( $wp_styles->queue as $style ) :
echo $wp_styles->registered[$style]->src . "<br/>";
endforeach;
}
任何东西都不起作用（Wordpress 5.x），它是一个只能删除的系统
style.css. 我想为我的插件找到一种方法来删除除WordPress管理栏之外的所有样式。
有人有主意吗？
最合适的回答,由SO网友:J.BizMai 整理而成
我找到了一种列出所有句柄的方法，然后，我选择了我想要保留的所有css来执行此功能：
//call in my object
add_action( \'wp_enqueue_scripts\', array( $this , "clean_styles" ), 9999 );
public function clean_styles(){
wp_debug_log();
global $wp_styles;
foreach( $wp_styles->queue as $style ) :
//List the css src and handle
//echo $wp_styles->registered[$style]->src . " - ";
//echo $wp_styles->registered[$style]->handle . "<br/>";
$handle = $wp_styles->registered[$style]->handle;
//array of css I want to keep
$css_exception = [ "wp-block-library", "wp-block-library-theme", "admin-bar" ]
if( !in_array( $handle, $css_exception ) ){
wp_dequeue_style( $handle );
wp_deregister_style( $handle );
}
endforeach;
//echo "<br/><br/>";
//List the css list I kept
/*foreach( $wp_styles->queue as $style ) :
echo $wp_styles->registered[$style]->src . "<br/>";
endforeach;*/
}
