我想创建一个简单的wordpress网站，在其中我想在页面上显示一个搜索框。在文本/搜索框中搜索字符串时，应基于该字符串进行外部API调用，并向用户显示API返回的数据。到目前为止，我已成功从以下URL引用代码-https://rapidapi.com/blog/integrate-external-api-wordpress/.

但我无法根据文本框中传递的字符串调用API。我在子主题文件页面中完成了以下代码：-

<div id="primary" <?php generate_do_element_classes( \'content\' ); ?>>
    <main id="main" <?php generate_do_element_classes( \'main\' ); ?>>
        <form action="" method="post">
        Enter query:
        <input type=text name="t1">
        <br>
        <br>
        <input type=submit name="s">
        <?php
        /**
         * generate_before_main_content hook.
         *
         * @since 0.1
         */
        do_action( \'generate_before_main_content\' );

        if(isset($_POST[\'s\'])){
        echo "good";    
        $curl = curl_init();

        curl_setopt_array($curl, [
            CURLOPT_URL => "******API URL*****/".$_POST[\'t1\'],
            CURLOPT_RETURNTRANSFER => true,
            CURLOPT_FOLLOWLOCATION => true,
            CURLOPT_ENCODING => "",
            CURLOPT_MAXREDIRS => 10,
            CURLOPT_TIMEOUT => 30,
            CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
            CURLOPT_CUSTOMREQUEST => "GET",
            CURLOPT_HTTPHEADER => [
                "x-rapidapi-host: XYZ",
                "x-rapidapi-key: ABc"
            ],
        ]);

        $response = curl_exec($curl);
        $err = curl_error($curl);

        curl_close($curl);

        if ($err) {
            echo "cURL Error #:" . $err;
        } else {
            echo $response;
        }
    }
                

        /**
         * generate_after_main_content hook.
         *
         * @since 0.1
         */
        do_action( \'generate_after_main_content\' );
        ?>
        </form>
    </main>
</div>

<?php
/**
 * generate_after_primary_content_area hook.
 *
 * @since 2.0
 */
do_action( \'generate_after_primary_content_area\' );

generate_construct_sidebars();

get_footer();